19x^2-250x+625=0

Solution for 19x^2-250x+625=0 equation:

19x^2-250x+625=0

a = 19; b = -250; c = +625;
Δ = b2-4ac
Δ = -2502-4·19·625
Δ = 15000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15000}=\sqrt{2500*6}=\sqrt{2500}*\sqrt{6}=50\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-250)-50\sqrt{6}}{2*19}=\frac{250-50\sqrt{6}}{38}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-250)+50\sqrt{6}}{2*19}=\frac{250+50\sqrt{6}}{38}
$